# Average Aptitude Questions with Solutions:- Set 1

__Average Aptitude Questions with Solutions: Set 01__

__Question No. 01__:

__Average Aptitude Questions with Solutions: Set 01__

__Question No. 01__

## The average age of 30 boys of a class is equal to 14 years. When the age of the class teacher is included the average becomes 15 years. Find the age of the class teacher.

## (A) 30 years (B) 35 years (C) 45 years (D) 52 years

## Answer: Option C

Explanation: Total age of 30 boys = 14 × 30 = 420 years

Explanation:

Explanation:

## Total age when the teacher is included = 15 × 31 = 465 years

## ∴ Age of the class teacher = 465 – 420 = 45 years

**Alternate Method: Direct Formula**

## Age of new entrant = New average + (No. of old members × change in average)= 15 + 30 (15 – 14) = 45 years.

__Question No. 02__:

__Question No. 02__

## The captain of a cricket team of 11 members is 26 years old and the wicket keeper is 3 years older. If the ages of these two are excluded, the average age of the remaining players is one year less than the average age of the whole team. What is the average age of the team?

## (A) 23 years(B) 24 years(C) 25 years(D) None of these

## Answer: Option A

Explanation: Let the average age of the whole team by *x* years.

Explanation:

Explanation:

## ∴ 11*x* – (26 + 29) = 9(*x* -1)=> 11*x* – 9*x* = 46=> 2*x* = 46=> *x* = 23.

## So, average age of the team is 23 years.

__Question No. 03__:

__Question No. 03__

## The average age of boys in the class is twice the number of girls in the class. If the ratio of boys and girls in the class of 36 be 5 : 1, what is the total of the ages (in years) of the boys in the class?

## (A) 380(B) 342(C) 372(D) 360

## Answer: Option D

Explanation: Number of boys = (36 × ^{5}/_{6}) = 30 years

Explanation:

Explanation:

## Numbers of girls = 6Average age of boys = (2 × 6) = 12 years

## Total age of boys = (30 × 12) years = 360 years.

__Question No. 04__:

__Question No. 04__

## A car owner buys petrol at Rs.7.50, Rs. 8 and Rs. 8.50 per litre for three successive years. What approximately is the average cost per litre of petrol if he spends Rs. 4000 each year?

## (A) Rs. 7.98(B) Rs. 8(C) Rs. 8.50(D) Rs. 9

## Answer: Option A

Explanation: Total quantity of petrol consumed in 3 years

Explanation:

Explanation:

## = {(4000/7.50) + (4000/8) + (4000/8.50)} litres

## = 4000 {(2/15) + (1/8) + (2/17)} litres

## = (76,700/51) litres

## Total amount spent = Rs. (3 × 4000) = Rs. 12,000

## ∴ Average cost = Rs. (12,000 × 51)/ 76,700

## = Rs. 6120/767

## = Rs. 7.98

__Question No. 05__:

__Question No. 05__

## In Ankit’s opinion, his weight is greater than 65 kg but less than 72 kg. His sister does not agree with Ankit and she thinks that Ankit’s weight is greater than 60 kg but less than 70 kg. His mother’s view is that his weight cannot be greater than 68 kg. If all are them are correct in their estimation, what is the average of different probable weights of Ankit?

## (A) 67 kg.(B) 68 kg.(C) 69 kg.(D) None of these

## Answer: Option A

__Explanation:__Let Ankit’s weight be *x* kg.According to Ankit, 65 < *x* < 72According to Ankit’s sister, 60 < *x* < 70According to Ankit’s mother, *x* ≤ 68The values satisfying all the above conditions are 66, 67 and 68.∴ Required average = (66 + 67 + 68)/3 = 201/3 = 67 kg.

__Explanation:__

__Question No. 06__:

__Question No. 06__

## Indian shooting team of 8 persons joins in a shooting competition. One of them scored 85 points. If he had scored 92 points, the average score for the team would have been 84. The numbers of points, the team scored was

## (A) 672(B) 665(C) 645(D) 588

## Answer: Option B

Explanation: Let the total score be x.Therefore, (*x* + 92 – 85)/8 = 84=> (*x* + 7) = 672=> *x* = 665

Explanation:

Explanation:

__Question No. 07__:

__Question No. 07__

## If the average marks of three batches of 55, 60 and 45 students respectively is 50, 55, 60, then the average marks of all the students is:

## (A) 53.33(B) 54.68(C) 55(D) None of these

## Answer: Option B

Explanation: Required average = {(55 × 50) + (60 × 55) + (45 × 60)} / (55 + 60 + 45)

Explanation:

Explanation:

## = (2750 + 3300 + 2700)/160

## = 8750/160

## = 54.68

__Question No. 08__:

__Question No. 08__

## Three years ago, the average age of Raju, Ranjan and Ravi was 27 years and that of Ranjan and Ravi, 5 years ago was 20 years. Raju’s present age is

## (A) 30 years(B) 35 years(C) 40 years(D) 48 years

## Answer: Option C

Explanation: Present age of (Raju + Ranjan + Ravi) = {(27 × 3) + (3 × 3)} = 90 years.

Explanation:

Explanation:

## Present age of (Ranjan + Ravi) = {(20 × 2) + (2 × 5)} = 50 years.

## Therefore, Raju’s present age = (90 – 50) = 40 years.

__Question No. 09__

__Question No. 09__

## The average monthly income of ‘P’ and ‘Q’ is Rs. 5050. The average monthly income of ‘Q’ and ‘R’ is Rs. 6250 and the average monthly income of ‘P’ and ‘R’ is Rs. 5200. The monthly income of ‘P’ is:

## (A) 3500(B) 4000(C) 4050(D) 5000

## Answer: Option B

Explanation: Let *P*, *Q* and *R* represent their respective monthly incomes. Then, we have:*P* + *Q* = (5050 × 2) = 10,100 …….. (i)

Explanation:

Explanation:

*Q* + *R* = (6250 × 2) = 12,500 …….. (ii)

*P* + *R* = (5200 × 2) = 10,400 …….. (iii)

## Adding (i), (ii) and (iii), we get: 2(*P* + *Q* + *R*) = 33,000 or *P* + *Q* + *R* = 16,500 …….. (iv)

## Subtracting (ii) from (iv), we get *P* = 4000.∴ *P*‘s monthly income = Rs. 4000

__Question No. 10__:

__Question No. 10__

## The average of 5 consecutive numbers is ‘*n*’. If the next two numbers are also included, the average will

## (A) Increase by 1(B) Remain same(C) Increase by 1.4(D) Increase by 2

## Answer: Option A

Explanation: Let, 5 consecutive numbers be, x, x+1, x+2, x+3 and x+4

Explanation:

Explanation: