With usual notations the depth of the neutral axis of a balanced section is given by

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VideRime Staff asked 4 years ago

With usual notations the depth of the neutral axis of a balanced section is given by

a) mc/t = (d-n) / n

b) t/mc = n / (d+n)

c) t/mc = (d+n)/n

d) mc/t = n/ (d-n) (Ans)

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